Let A(i|j) denote the matrix obtained by deleting row i and column j from a parent matrix A. Define tij to be the number of transversals in L(i|j), for some fixed Latin square L. We show that tab= tcd mod 2 for all a,b,c,d and L. Also, if L has odd order then the number of transversals of L equals tab mod 2. We conjecture that tac + tbc + tad + tbd = 0 mod 4 for all a,b,c,d.
In the course of our investigations we prove several results that could be of interest in other contexts. For example, we show that the number of perfect matchings in a k-regular bipartite graph on 2n vertices is divisible by 4 when n is odd and k=0 mod 4. We also show that per A(a|c)+per A(b|c)+per A(a|d)+per A(b|d) = 0 mod 4 for all a,b,c,d, when A is an integer matrix of odd order with all row and columns sums equal to k=2 mod 4.